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0.92=5x^2-2x
We move all terms to the left:
0.92-(5x^2-2x)=0
We get rid of parentheses
-5x^2+2x+0.92=0
a = -5; b = 2; c = +0.92;
Δ = b2-4ac
Δ = 22-4·(-5)·0.92
Δ = 22.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{22.4}}{2*-5}=\frac{-2-\sqrt{22.4}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{22.4}}{2*-5}=\frac{-2+\sqrt{22.4}}{-10} $
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